x^2+(y+3)x+4y=0

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Solution for x^2+(y+3)x+4y=0 equation: 


Simplifying
x2 + (y + 3) * x + 4y = 0

Reorder the terms:
x2 + (3 + y) * x + 4y = 0

Reorder the terms for easier multiplication:
x2 + x(3 + y) + 4y = 0
x2 + (3 * x + y * x) + 4y = 0
x2 + (3x + xy) + 4y = 0

Reorder the terms:
3x + xy + x2 + 4y = 0

Solving
3x + xy + x2 + 4y = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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